Wiring switch to control two components

Spiff4565

Active member
On my first Guvernator build, I installed 4k7 instead of 47k resistors in T101 and R102.

The 4k7's produced a lower gain effect than the 47k's, so I was thinking about using a foot switch that would toggle between these two components.

I'm not sure there is a foot switch that would support this function, and if so, how it would be wired up. There is a 4DPDT foot switch but not sure this would work or how to wire it if it would work. Can't find any wiring schematics for the 4DPDT foot switch.

Thoughts?
 
All you need is a dpdt on/on or a 3pdt if you want to use a led for indication.
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Looking at the dpdt, solder both the 4k7 and 47k to one shared pad. Run 1 wire from the other unpopulated resistor pad to a center lug, let's say lug 2.
Run a wire from lug 1 to the free lead of one resistor and a wire from lug 3 to the other resistor.
Repeat on another set of lugs for the other 2 components, keeping the low gain components on one side of the switch and high gain components on the other side.
 
Thank you for the information. Greatly appreciated.

Now then, let's take this up a notch. If I were to get a duo colored LED, would it be possible to incorporate that into the switch?

Say for example on the lower gained side of the switch, blue LED. When high gained side of switch is engage the LED would be red.
 
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To add the dual-LED just bump up to a 3PDT.

Bring +9V (through an appropriate current limiting resistor) to center lug 8 (per above diagram). Tie your LED cathode (short leg) to ground as normal, and tie the two separate anodes (long legs) to lugs 7 and 9 respectively.

You may want to think about where to pull that +9V from, depending if you want the gain level indicator LED to still be on or not when the effect is in bypass.
 
To add the dual-LED just bump up to a 3PDT.

Bring +9V (through an appropriate current limiting resistor) to center lug 8 (per above diagram). Tie your LED cathode (short leg) to ground as normal, and tie the two separate anodes (long legs) to lugs 7 and 9 respectively.

You may want to think about where to pull that +9V from, depending if you want the gain level indicator LED to still be on or not when the effect is in bypass.
I would do this inverted and use a common anode bicolor. Then switch ground on the 3pdt. No chance of shorting DC to your input or output that way
 
Ideally the gain LED would stay on when the circuit is bypassed. But for now that would just be icing on the cake.

First thing will be to get the two different resistors working and see how the arrangement works. It may be a complete wreck, in which case the rest is moot.
 
I would do this inverted and use a common anode bicolor. Then switch ground on the 3pdt. No chance of shorting DC to your input or output that way
Yeah that does sound better. I’ve never used one myself. Just googled bi-color LED and found the common cathode version. Didn’t realize you could also get the opposite;)
 
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