I may have a spare 470nF film cap, need to root around.
So, following the schematic, it looks like the positive leg of the 1uF cap will go to the middle leg of the transistor. In case I run into something like this in the future or can't find a 470nF cap, does that mean the negative leg is "in" and the positive leg is "out" with respect to the circuit?
Last but not least (sorry, I'm a novice with this stuff); how does the 470nF cap affect the circuit? Why 470nF and not some other value?