I’ve been working on a dual pedal and wanted to use a bi-color led to indicate which way the effect was running; A-B vs B-A..
My though was simple, and was to reproduce the standard power LED circuit through the foot switch. So started testing with a 9V supply and a 4K7 resistance. I noticed the green side of the led was really faded…. So I wonder if I could supply more current to the LED to get it brighter.
After calculation I ended up with a current value of 2mA with a 4K7 (4700 / 9 = 0.0019). The led spec are for 20mA, so my question is:
Why do we use such a high resistance in our circuit ?
If I were to use an 800R it would give me about 11mA… well within tolerance of the led….
So why ?
My though was simple, and was to reproduce the standard power LED circuit through the foot switch. So started testing with a 9V supply and a 4K7 resistance. I noticed the green side of the led was really faded…. So I wonder if I could supply more current to the LED to get it brighter.
After calculation I ended up with a current value of 2mA with a 4K7 (4700 / 9 = 0.0019). The led spec are for 20mA, so my question is:
Why do we use such a high resistance in our circuit ?
If I were to use an 800R it would give me about 11mA… well within tolerance of the led….
So why ?