Illuminated 3DPT breakout board on PCB w/o LED mount

JohnDRhoads33

New member
Hello,

So, I am working on a PCB clone of an EQD Talons, except the board doesn't have a place for an LED already on it, and I want to use an illuminated 3PDT footswitch on this build. I assume it's simple and using the board that doesn't have a location for an LED already, it would mean that to use the illuminated 3PDT I would have to simply add the resistor (assuming a 1K or 820R) between the SW spot on the PCB to the SW location on the 3DPT breakout board? Something like this horrible mockup? It's an Eaglet from Rullywow if that helps.

1628017338742.png
 
No resistor necessary, your PCB already has a resistor for the LED. If you're using the LED breakout board, you simply need to jumper where the LED goes on the PCB.
 
In case you looked at the PCB on their site, the LEDs that are actually on the PCB are used as clipping diodes, and I imagine they will only light up as you play and put signal through.
 
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