mdc
Well-known member
Hi folks,
When using RG147 coaxial as for I/O wiring, I've seen it recommended quite often to only connect one end of the shielding to ground, but not the other.
I'm curious as to the theory/science behind this—can anyone explain the reasoning?
So in practice, say I've got a mono input jack, a PCB with a ground pad for the input, and then a ground connection via the footswitch...
I connect the RG147 to the + lug on the jack (with the shielding tied off); then run it to the normal spot on the 3PDT, with the shielding then going to ground on the footswitch.
Do I then run a separate ground wire from the - lug on the input jack to the appropriate ground pad on the board? Or would I leave the input ungrounded completely at the jack?
I've also seen some back and forth about whether the output jack should be connected to the shielding on one or both ends, with no clear conclusion.
Anyway, if someone has a handy MS Paint drawing and some reasonable sounding science to pass along I'd be very grateful.
When using RG147 coaxial as for I/O wiring, I've seen it recommended quite often to only connect one end of the shielding to ground, but not the other.
I'm curious as to the theory/science behind this—can anyone explain the reasoning?
So in practice, say I've got a mono input jack, a PCB with a ground pad for the input, and then a ground connection via the footswitch...
I connect the RG147 to the + lug on the jack (with the shielding tied off); then run it to the normal spot on the 3PDT, with the shielding then going to ground on the footswitch.
Do I then run a separate ground wire from the - lug on the input jack to the appropriate ground pad on the board? Or would I leave the input ungrounded completely at the jack?
I've also seen some back and forth about whether the output jack should be connected to the shielding on one or both ends, with no clear conclusion.
Anyway, if someone has a handy MS Paint drawing and some reasonable sounding science to pass along I'd be very grateful.