vigilante398
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I had planned to add this post on to the previous post about tube preamp design, but as I was writing it I found it getting way longer than I had planned, so I figured I would make it a separate topic.
So how do I power these tubes?
Well let’s start with the heater, without that you won’t be getting any signal regardless of what you put on the plates. The heater is also known as the filament, but I’m used to calling it heater, so that’s what I’m going to continue to do.
Our 12AX7 dual triode has three connections for the heater, the two ends and a center tap. It may help to think of the heaters as a pair of resistors forming a resistor divider.
Since the only goal is to get it hot, and resistors are non-polarized, you can either use AC or DC to heat it up, the heaters don’t care. The only important thing is that there needs to be approximately 6.3V between pin 4 and pin 9, and 6.3V between pin 5 and pin 9. There are two common ways to do this. In amplifiers it’s common to have a 6.3V transformer winding on your power transformer, so you can tie pins 4 and 5 together, and connect your 6.3V AC lines to pin 9 and your combined pins 4/5.
In pedals we’re a lot more likely to have DC running around in the pedal, and it’s not uncommon to run a pedal at 12V. So in this case we leave the center tap unconnected and connect +12VDC to one heater pin and GROUND to the other heater pin.
I’ve also seen (and built) plenty of pedals that take a 9V input and step it down to 6V using a regulator like L7806 and do the same setup as found on amplifiers.
One trick I’ve seen to get exactly 6.3V is to add a diode between the regulator’s ground pin and ground to adjust the voltage. A schottkey diode with a 300mV forward voltage would give you exactly what you’re looking for. I’ve seen this in one DIY project (TH Customs if I remember right) and it works, but I don’t generally recommend it as it removes the heatsink of the regulator from ground, so it’s harder for it to dissipate the heat it’s going to generate. But it’s a neat academic exercise.
So how much current is the heater going to pull?
It’s Ohm’s Law time! On a 12AX7 (or similar dual triode in the same family) the nominal resistance of the filaments is 42ohms on each side. So if you power it with 12.6V like the datasheet recommends, it puts both resistances in series to give us 84 ohms, and we have
I = V/R
I = 12.6/84
I = 0.15 = 150mA
If we’re running the heaters off 6.3V we have the two resistances in parallel, which gives us an equivalent resistance of 21 ohms, so we have
I = V/R
I = 6.3/21
I = 0.3 = 300mA
So in pedals where current draw is often a big consideration, as we have to power them somehow and many pedal supplies are very limited in output, it makes sense to use the method that will pull the least amount of current. This is why it’s common to use a 12V supply for tube pedals. But…
How critical is the heater voltage?
Not very! The datasheet calls for 12.6V or 6.3V but we commonly use a straight 12V or 6V. How low can we actually go? We can absolutely get away with powering a 12AX7 with 9V on the heater instead of 12V! This is the way I chose to hook up heaters in my pedals, so every tube pedal I make runs the heaters in series straight off the 9V supply. This gives us an additional advantage in current draw, since with a 9V supply:
I = V/R
I = 9/84
I = 0.107 - 107mA
When we use a lower voltage for the heater supply, as long as it's still high enough to heat the tube, we can save power since the heaters are fixed resistances. To be completely honest I have no idea what the "minimum" voltage is before you start noticing a difference in sound, but 9V gives no audible difference compared to 12V and only pulls 107mA on the heater as opposed to 150mA on a 12.6V supply.
Does it matter which pin is positive and which pin is negative?
Nope! Remember the heater is like a resistor, there’s no polarity, there just needs to be the right voltage between the two points.
So how do I power these tubes?
Well let’s start with the heater, without that you won’t be getting any signal regardless of what you put on the plates. The heater is also known as the filament, but I’m used to calling it heater, so that’s what I’m going to continue to do.
Our 12AX7 dual triode has three connections for the heater, the two ends and a center tap. It may help to think of the heaters as a pair of resistors forming a resistor divider.
Since the only goal is to get it hot, and resistors are non-polarized, you can either use AC or DC to heat it up, the heaters don’t care. The only important thing is that there needs to be approximately 6.3V between pin 4 and pin 9, and 6.3V between pin 5 and pin 9. There are two common ways to do this. In amplifiers it’s common to have a 6.3V transformer winding on your power transformer, so you can tie pins 4 and 5 together, and connect your 6.3V AC lines to pin 9 and your combined pins 4/5.
In pedals we’re a lot more likely to have DC running around in the pedal, and it’s not uncommon to run a pedal at 12V. So in this case we leave the center tap unconnected and connect +12VDC to one heater pin and GROUND to the other heater pin.
I’ve also seen (and built) plenty of pedals that take a 9V input and step it down to 6V using a regulator like L7806 and do the same setup as found on amplifiers.
One trick I’ve seen to get exactly 6.3V is to add a diode between the regulator’s ground pin and ground to adjust the voltage. A schottkey diode with a 300mV forward voltage would give you exactly what you’re looking for. I’ve seen this in one DIY project (TH Customs if I remember right) and it works, but I don’t generally recommend it as it removes the heatsink of the regulator from ground, so it’s harder for it to dissipate the heat it’s going to generate. But it’s a neat academic exercise.
So how much current is the heater going to pull?
It’s Ohm’s Law time! On a 12AX7 (or similar dual triode in the same family) the nominal resistance of the filaments is 42ohms on each side. So if you power it with 12.6V like the datasheet recommends, it puts both resistances in series to give us 84 ohms, and we have
I = V/R
I = 12.6/84
I = 0.15 = 150mA
If we’re running the heaters off 6.3V we have the two resistances in parallel, which gives us an equivalent resistance of 21 ohms, so we have
I = V/R
I = 6.3/21
I = 0.3 = 300mA
So in pedals where current draw is often a big consideration, as we have to power them somehow and many pedal supplies are very limited in output, it makes sense to use the method that will pull the least amount of current. This is why it’s common to use a 12V supply for tube pedals. But…
How critical is the heater voltage?
Not very! The datasheet calls for 12.6V or 6.3V but we commonly use a straight 12V or 6V. How low can we actually go? We can absolutely get away with powering a 12AX7 with 9V on the heater instead of 12V! This is the way I chose to hook up heaters in my pedals, so every tube pedal I make runs the heaters in series straight off the 9V supply. This gives us an additional advantage in current draw, since with a 9V supply:
I = V/R
I = 9/84
I = 0.107 - 107mA
When we use a lower voltage for the heater supply, as long as it's still high enough to heat the tube, we can save power since the heaters are fixed resistances. To be completely honest I have no idea what the "minimum" voltage is before you start noticing a difference in sound, but 9V gives no audible difference compared to 12V and only pulls 107mA on the heater as opposed to 150mA on a 12.6V supply.
Does it matter which pin is positive and which pin is negative?
Nope! Remember the heater is like a resistor, there’s no polarity, there just needs to be the right voltage between the two points.