50k pot in place of 25k pot?

djmiyta

Well-known member
I subbed 2 B25k pots for the 2 C25k pots in my Vallhalla build and want to get the right ones in there, Again I'm having problems so can I put C50k in instead of C25k without any problems?
 
You can also take a 50k pot and tune it down to 25k by soldering a 50k resistor between lugs 1 and 3 this workS better on a linear pot than a log. But as long as you aren’t trying to change the value to drastically it works just fine on a logarithmic pot.
 
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I’m sure it depends on what the pots doing in the circuit but will changing the value even tho it’s not much have any affect on how it sounds cause I dig mine and if it does I’ll leave it be they’re B25k’s instead of C25k now thought I might have a bit more control with the C’s in there
 
From my experience, a pot with that little difference won't hinder anything or make it scream out of control. You could go the 50k resistor route to see what you think. It's all about the DIY.
 
With C25 potentiometer you have following values vs position.
max CCW - 25k (23k5 measured)
9 o'clock - 18k
12 o'clock - 3k5
15 o'clock - 400R
max CW - 0

and simiar data for the C50k with 51k resistor across 1-3 (but with 1 and 2 shorted as in Valhalla)
max CCW - 25k (24k measured)
9 o'clock - 20k1
12 o'clock - 6k
15 o'clock - 1k
max CW - 0

And here you have comparison between C25k and B25k potentiometers (5 plots for each set, ltspice step funcion).
DEEP potentiometer
1637349024703.png

PRES potentiometer
1637349268050.png

Now, DEEP with values measured from real potentiometers - C25k and C50k + 51k resistor

1637350812230.png

Still better than B25k :)
 
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