Footswitch Instead of Toggle…

fig said:
what opamp is that please?
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741.
Mcknib said:
Sounds like it may be a poor connection check your LED ground connections

The voltage drop across the resistor would be supply voltage less LED fwd voltage

So for yours one side would be 9v less 1.99v or 7.01v dropped and obviously 9v less 1.91v or 7.09v dropped because with a bi colour only one side lights at a time, on the LED side of the resistor you would get a voltage reading of whatever the voltage drop of the side being used is

If the circuits incomplete ie not grounded you'd get full voltage because it's got no where to go so maybe a bad connection somewhere breaking the circuit
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Right now I have a 4k7 hooked up to the 9v. DMM from opposite 4K7 side to the power jack negative lug reads 9v.
 
No apology necessary sir.
Coda said:
Right now I have a 4k7 hooked up to the 9v. DMM from opposite 4K7 side to the power jack negative lug reads 9v.
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Yes, as it should because there is no load correct?. Add the LED in series and check again. At the node where the resistor and LED meet, you should see a voltage drop.
 
Coda said:
Right now I have a 4k7 hooked up to the 9v. DMM from opposite 4K7 side to the power jack negative lug reads 9v.
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If there’s just a single resistor and nothing else then then you should have no voltage drop across the resistor, and a current draw of ~1.9mA

Remember Ohm’s law— V=IR
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*disclaimer: I just woke up from a nap, so I’m very possibly completely mistaken
 
The way you've got the LEDs connected in the schematic would work I don't see any reason why it shouldn't as long as the CLRs are 4K7 it'll only allow the current needed to illuminate them
 
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