School me on C and W tapers behavior

[thomasbe86]

I am trying to find the best fit for a potentiometer within my circuit, but really, in simulation I only ever use A and B taper... I never really understood how the others work...

Here are the graphs with both tapers; I am greedy and looking for a more precise transistion on the early course of the pot, like "extra" log...
Basically; the lower the resistance, the louder the hump at 130Hz
Can anyone give me a clue on what each value would look like for C and W tapers? table at the end is what ChatGPT told me they behave like for a 100k pot, not sure this sounds correct...

 

[BuddytheReow]

It’s easier to show graphically. C tapers are the opposite of A tapers, where the resistance increases quickly then slows down as you turn clockwise. K tapers are a hybrid of linear and logarithmic(?) where half the sweep mimics one taper then switches to the other. Any taper pot will work in any given circuit as long as the value is correct. The difference is how it behaves as you turn it. Some linear pots don’t do much until the last quarter turn. C tapers would be a good substitution there.

https://eepower.com/uploads/education/potentiometer_taper.png

 

[thomasbe86]

Ok, so confirmation on what I showed on the table for C taper, which makes the graph look like this, exactly the opposite of what I'd love:
Has anyone ever managed to simulate an "extra" log taper? I tried several combinations with different tapers and resistors in parallel but this just makes it worse....

 

[Silver Blues]

1) is your standard linear "B" taper,
2) is your standard logarithmic or "audio" "A" taper (which is ironic because that curve is not a logarithmic function),
4) is the reverse-log or "C" taper (which is really more like a logarithmic function),
5) is a "W" taper, sort of sigmoidal where you have a reverse-log taper from 0-50 and a log taper from 50-100.