Simple high pass filter question

Locrian99

Well-known member
Just wanting to do a simple high pass filter that is passive and would be in its own box.

Goal is -6db at 90hz. Which i can get close enough here. Do I need to use Rin and RL ?
IMG_1933.png
 
Rin and RL depend on the impedance of whatever is before and after. Ideally you assume 0 for Rin if a buffer or active pedal (with low outpu impedance) is before it, and 1M for RL, as most pedals and amps have 470k~1M input impedace. But, if you're putting this first in chain (connected directly to the pickups), then the output impedance of the pickups will make a big difference.

A lot of calculators ignore Rin and RL and just calculate the RC, assuming low Rin and high RL.

A first-order filter calculator like that will tell you the cutoff frequency where the output is -3db. You'd have to set the cutoff freqency higher that 90hz to get -6db reduction at 90hz.

A 2nd order filter will be steeper, and I believe the cutoff frequency from a calculator tool will be at -6db. The pedalpcb Frequency Interchanger uses 2nd order (or 2-pole) for the highpass filter (Sallen & Key style).
 
Just saw Cybercow's, he covered some of the same things.
My understanding is an active 2nd order filter will be steeper and more defined than 2 cascading 1st orders filters, I'd guess better for your application
 
K cool the roll off can start a bit higher I think I can play with it. With 10k and 100n im showing -6.4db at 90 hz and the roll off looks gradual enough. Guess I’ll just see how it sounds.
 
This is the tone stack calculator i was using to find where -6 at 90hz was

 
This is a really good video series on filter basics:
It’s from a synthesizer perspective, but it mostly all still applies to pedals.
He goes from passive filters all the way through to active resonant filters with CV control.
It’s really easy to follow, and you can just stop whenever you get to the level of filter complexity you’re looking for ;)
 
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